SOLVED: Consider the balanced equation for the reaction of aluminum with hydrochloric acid: 2Al 6 HCl -> 2 AlCl3 3 H2. Fill in the conversion factors required to calculate the mass of HCl needed to react with 5.00 g of Al. A) 5.00 g Al x (1 mol Al / 26.9815 g Al) x (6 mol HCl / 2 mol Al) x (36.454 g HCl / 1 mol HCl)
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