Jul 6, 2015 · tan(60°)=sqrt(3) Have a look: How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle?

Click here👆to get an answer to your question ️ tan a tan 60a tan 60a is equal to

tanA+tan(60+A)+tan(60-A)=3tan3A. View Solution. Q5

Range of Trigonometric Ratios from 0 to 90 Degrees. Question. Evaluate each of the following : tan 2 60 ∘ + 4 cos 2 45 ∘ + 3 sec 2 30 ∘ + 5 cos 2 90 ∘ cosec 30 ∘ + sec 60 ∘ − cot 2 30 ∘

Click here:point_up_2:to get an answer to your question :writing_hand:prove that tan theta tan 60otheta tan 120otheta3 tan 3 theta

Sep 3, 2016 · sqrt3 tan60 = sin60/cos60 = (sqrt3/2)/(1/2) = sqrt3. How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle?

Oct 18, 2017 · sqrt3 Use trig identity: tan 2a = (2tan a)/(1 - tan^2 a) In this case: tan (60) = (2tan (30))/( 1 - tan^2 30) Trig table gives --> tan 30 = sqrt3/3 --> tan^2 30 = 3/9 ...

Click here:point_up_2:to get an answer to your question :writing_hand:the value of tan 30circ tan 60circ is

cos 60 o + sin 60 o + tan 60 o + cot 60 o + sec 60 o + csc 60 o. View Solution. Q5.

tanA+tan(60+A)+tan(60-A)=3tan3A. View Solution. Q4