Oct 14, 2015 · At this point calculating formal charge of those two coordinate bonded oxygen gives total formal charge of −2 and the formal charge on $\ce S$ and the double bonded $\ce O$ is zero. Thus the minus 2 charge on $\ce{SO4^2-}$ can be shown but initially all the atoms were neutral. While making bonds electrons were shared only.

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Mar 20, 2019 · This leaves behind the sulfate ion: $$\ce{H2SO4 -> 2H+ + SO4^2-}$$ When the $\ce{H^+}$ ion departs, it leaves its electron behind, so it has to go somewhere (it remains with the $\ce{O}$ atom). Hypothetically if $\ce{SO4}$ existed, with all $\ce{O}$ atoms double-bonded to the $\ce{S}$ , then the sulfur would have a total of 16 electrons in its ...

Sep 5, 2015 · $$\ce{HSO4- (aq) + H2O <-> H3O+ (aq) + SO4^2- (aq)}$$ The sulfate ion should be a weak conjugate base, and hence the sodium sulfate salt should be a weak base. This was my line of reasoning, until today my friends told me it is actually a neutral salt, which was confirmed by searching online.

Jun 17, 2018 · My question is, why can't the dissociation reaction happen like this: $$\ce{H2SO4 -> 2H^+ +SO4^{2-}}$$ I know hydrogen is a diatomic gas, but here I don't know if H will dissociate as a gas or as a liquid (since $\ce{H2SO4}$ is a liquid, not a gas).

Aug 17, 2017 · Basically $\ce{CuSO4}$ already exists as $\ce{Cu^{2+}}$ and $\ce{SO4^{2-}}$. It's anhydride form exists as an orthorhombic arrangement of ions. The opposite charge attraction balances the like-charge repulsions and the crystal stays bound. When you dissolve it into water, a few things happen.

The S-O bond length in $\ce{SO4^{2-}}$ is 149 pm, which is shorter than that observed in sulfuric acid (157 pm) and very close to the gas-phase bond length of sulfur monoxide which is 148 pm. So, at the end of the day, an electron dot structure is a type of model that describes bonding.

For the chemical reaction, Fe2O3 + 3 SO3 à Fe2(SO4)3, calculate the number of moles of SO3 you will need to completely react with 6.45 moles of Fe2O3. Select the closest value. arrow_forward

Calculate the ratio of moles of H2O to moles of anhydrous KAl(SO4)2. Show all work to answer this question by uploading an image of your calculations into Photo 3. Note: Report the ratio to the closest whole number. Write the empirical formula for the hydrated KAl(SO4)2, based on your experimental results and answer to Question 2.

In the equation $\ce{2SO4^2- -> S2O8^2- + 2e-}$ sulfate is being oxidized. This is different from oxygen being oxidized. The statement in the OP "In this reaction 2 of the oxygen ions change from $-2$ to $-1$ " is incorrect. Instead, each sulfate ion, taken as a whole, loses 1 electron.