Sep 11, 2015 · It is -sqrt3/2 We have that sin300=sin(360-60)=sin360*cos60-cos360*sin60=0-sin60=-sqrt3/2

Feb 17, 2015 · sin is an odd function meaning that: sin(-x)=-sin(x) You have sin(300°) but 300°=360°-60° or -60° so you get: sin(300°)=sin(-60°)=-sin(60°)=-sqrt(3)/2

May 25, 2015 · Use the trig unit circle as proof. #sin 300 = sin (-60 + 360) = sin (-60) = -sin 60 =# # (-sqrt3)/2# #cos 300 = cos (-60 + 300) = cos 60 = 1/2#

You can put this solution on YOUR website!-sin 60. sin 270 is -1, and 300 degrees is the equivalent of 60 degrees here.

Jan 9, 2017 · cos 300 = 1/2 sin 300 = - sqrt3/2 tan 300 = - (4sqrt3)/3 Use trig table of special arcs and unit circle --> cos 300 = cos (-60 + 360) = cos (-60) = cos (60) = 1/2 sin ...

sin300 degrees . Algebra -> Trigonometry-basics-> SOLUTION: Use reference angles to find the exact value ...

Jul 7, 2018 · color(cyan)(=> sqrt2 I quadrant - All +, II quadrant - sin, csc +, III quadrant - tan, cot +, IV quadrant - cos, sec + sin 300^@ = sin (360 - 300) = -sin 60 = -sqrt3 ...

May 11, 2018 · Here, #sin300^circ=sin(360^circ-60^circ)...toIV^(th)Quadrant# #color(white)(sin300^circ)=-sin60^circ...tosin < 0#

Jan 4, 2017 · How do you find the exact value of the expression #sin330^circcos30^circ-cos330^circsin30^circ#?

Mar 7, 2018 · #sin 330 cos 120 + cos 210 sin 300# #=> (sin (360 - 30) * cos (180 - 120)) + (cos (180+ 30) * sin (360 - 60)# ...