Jan 26, 2017 · 1/e lnx=-1=>log_(e)x=-1 =>e^(-1)=x :.x=1/e. 141132 views around the world ...

Dec 15, 2014 · Lets start by breaking down the function. (ln(x))/x = 1/x ln(x) So we have the two functions; f(x) = 1/x g(x) = ln(x) But the derivative of ln(x) is 1/x, so f(x) = g'(x). This means we …

Nov 14, 2015 · Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e. 1 Answer . mason m

Mar 17, 2018 · See below. Using the exponential at both sides as the inverse of ln we obtain e^x = x but y = e^x and y = x does not intersect so no real solution for x = lnx

Mar 24, 2015 · You know that if #x>1 ln(x)>0# so the limit must be positive. You also know that #ln(x_2)-ln(x_1)=ln(x_2/x_1)# so if #x_2>x_1# the difference is positive, so #ln(x)# is always …

I found: x=e^e=15.154 You can use the definition of logarithm: log_ax=b->x=a^b and the fact that ln=log_e where e=2.71828...: we can write: ln(ln(x))=1 ln(x)=e^1 x=e^e=15.154

Nov 6, 2016 · The derivative of x^(lnx) is [(2*y*(lnx)*(x^(lnx)))/x] let y =x^(lnx) There are no rules that we can apply to easily differentiate this equation, so we just have to mess with it until we …

Dec 8, 2007 · How do you go about deriving the series expansion of ln(x)? 0 < x I got the representation at math.com but i'd still like to know how they got it. It's been a while since i did …

Jan 7, 2017 · color(magenta)"x = 0.050" Let's use the diagram below: This photo tells us that the natural log (ln) and the exponential function (e^(x)) are inverses of each other, which means …

Oct 23, 2015 · It's x. The logarithm and the exponential are inverse function, which means that if you combine them, you obtain the identity function, i.e. the function I such that I(x)=x. In terms …