Nov 23, 2016 · csc^2x-1 is equal to cot^2x Use the identity: sin^2x+cos^2x=1 Divide each term in the identity by sin^2theta 1+cot^2x=csc^2x Subtract 1 from each side: cot^2x=csc^2x-1

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x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} …

prove\:\cot(2x)=\frac{1-\tan^2(x)}{2\tan(x)} prove\:\csc(2x)=\frac{\sec(x)}{2\sin(x)} prove\:\frac{\sin(3x)+\sin(7x)}{\cos(3x)-\cos(7x)}=\cot(2x)

cot ^2 (x) + 1 = csc ^2 (x) sin(x y) = sin x cos y cos x sin y cos(x y) = cos x cosy sin x sin y

How do you simplify the expression \displaystyle\frac{{{1}-{\csc{{x}}}}}{{{1}-{{\csc}^{{2}}{x}}}} ?

\left(-\csc(2x^{1})\right)\cot(2x^{1})\times 2x^{1-1} The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0.

How do you simplify the expression \displaystyle{{\csc}^{{2}}{x}}-{1} ? https://socratic.org/questions/how-do-you-simplify-the-expression-csc-2x-1 …

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Sep 21, 2015 · Simplify: csc^2 x - 1 Ans: cot^2 x 1/sin^2 x - 1 = (1 - sin^2 x)/sin^2 x = cos^2 x /sin^2 x = cot^2 x