Oct 6, 2011 · (111) plane in BCC does not cut the center atom. But i do some geometry and i come about that the perpendicular distance from the center of that atom to the (111) plane is 2/3 of the radius of atom. So from my point of view it should cut the atom (since the distance is less than the radius of the atom).

Oct 28, 2006 · The [111] plane is a plane that touches the three far corners of the unit cell and it looks like a triangle. There are then a total 1/6*3 atoms that make up the vertices of the triangle and there are a total of 1/2*3 atoms that make up the three edges of the triangle. So you have a net total of 2 atoms inside the triangle.

Sep 8, 2008 · Homework Statement Niobium Nb has the BCC crystal with a lattice parameter of a= .3294 nm Find the planar concentrations of atoms per m^2 of the (100, (110) and (111) planes. The 100 plane has 1 atom on the plane (1/4 times 4) …

Jan 17, 2009 · I came up with this by assuming that atoms touch each other in the [111] direction in a BCC structure. In this direction [111] there is one atom that goes through the (1/2,1/2,1/2) position and half an atom at the origin and half an atom at the (1,1,1) position summing to 4 half's of an atom in length. using the answer 4R I got the lattice ...

Jan 23, 2012 · Calculate the surface density of atoms on (111) and (110) planes for the following crystal structure. a) simple cubic, b) body-centered cubic, c)face-centered cubic. Assume the lattice constant is x. Homework Equations well, from reading my lecture notes the general formula for surface density is (#atoms/cm2) .

Sep 24, 2008 · Slip can occur on other planes, but it's especially easy for a dislocation to move in the close-packed direction along a close-packed plane. For fcc crystals, this means {111}<110>. For bcc, it's {110}<111> (the close-packed direction on the closest-packed plane--there is no perfectly close-packed plane in bcc).

Oct 12, 2010 · In BCC, the close-packed planes are the {110} planes, and the close-packed directions are the <111> In FCC, the close-packed planes are the {111} planes, and the close-packed directions are the <110> direction

Sep 28, 2015 · For the (100), (110), and (111) planes of a Silicon crystal sketch the placement of atoms on the plane and determine the atom density (atoms/cm^2) on the plane. Homework Equations As of now I think the only relavent equation would be the atom density which is: Atoms per unit cell / (area of the square = Atoms per unit cell/a^2

Feb 20, 2015 · Prove that the lattice planes with the greatest densities of points are the {111} planes in a fcc bravis lattice and the {110} planes in a bcc bravis lattice. Homework Equations d/v=points per unit area where d is the spacing of planes and v is the unit volume. The Attempt at a Solution In the fcc case [tex] d=\frac{2\pi}{hb_1+kb_2+lb_3}\\

Apr 9, 2010 · My problem is that I have to study the system for different orientations of the crystal i.e. (100) plane, (110) plane and (111) planes. For (100), the initial configurations is simple. However, I would like to know, how I can create an initial configuration where the crystal is oriented along (110) plane or (111) plane?