
What is the derivative of #y=arccsc(x)#? - Socratic
Aug 3, 2014 · dy/dx = -1/sqrt(x^4 - x^2) Process: 1.) y = "arccsc"(x) First we will rewrite the equation in a form that is easier to work with. Take the cosecant of both sides: 2.) csc y = x …
Basic Inverse Trigonometric Functions - Trigonometry - Socratic
The basic inverse trigonometric functions are used to find the missing angles in right triangles. While the regular trigonometric functions are used to determine the missing sides of right …
What is the derivative of #y = arccsc (x/2)#? - Socratic
Jun 30, 2016 · - 2/(x sqrt(x^2 - 4)) if y = csc^{-1} (x/2) then csc y = x/2 [..... Which means that color{red}{sin y = 2/x}] so D_x(csc y = x/2) \\implies - csc y \\ cot y \\ y ' = 1/2 [D_z (csc z) = - …
How do you integrate #arcsec(x)#? - Socratic
Mar 9, 2015 · Method: To integrate #arc sec (x)#, substitution, then integrate by parts.. You'll also need #int secu du#, which can be done by substitution and partial fractions.
Differentiating Inverse Trigonometric Functions - Socratic
The derivatives of inverse trigonometric functions can be computed by using implicit differentiation followed by substitution.
Is arcsin(x) = csc(x) true? - Socratic
Oct 21, 2015 · #arcsin(x) = sin^-1(x)# is the inverse function of the function #sin(x)# That is: If #x in (-pi/2, pi/2)#, then #arcsin(sin(x)) = x#
How do you find the value of #sin (arc sec(x))#? - Socratic
Nov 23, 2016 · sin(arcsec(x))=sqrt(x^2-1)/x arcsecx means the angle whose secant ratio is x i.e. if arcsec(x)=theta, we have sectheta=x.
How do you differentiate y= arctan sqrt(x^2 -1) + "arccsc"\ x ...
Nov 15, 2017 · Original syntax: How do you differentiate #y= arctan sqrt(x^2 -1) + arccsc x#?. Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions
If arctan (3/5) = X, what is arccsc (cotan X)? - Socratic
Feb 26, 2016 · 36^@87 tan X = 3/5 --> cot X = 5/3 arccsc (5/3) = arcsin (3/5) Calculator --> sin y = 3/5 --> arc y = 36^@87
How do you graph #y = arcsec(x)#? - Socratic
Jul 17, 2018 · See graph and my idiosyncratic explanation. y = arcsec x = arc cos(1/x) , Conventionally limited ( for trigonometric arccos ) y in [ 0, pi ].