Apr 13, 2018 · tan 90 = oo ! [http://www.suresolv.com/basic-maths/basic-and-rich-trigonometry-concepts-and-its-applications] () tan 90 = sin 90 / cos 90 = 1 / 0 = oo

Nov 27, 2015 · tan90^@ is undefined. ! [http://www.coolmath.com/precalculus-review-calculus-intro/precalculus-trigonometry/28-the-unit-circle-01] () Since the angle is 90^@, there will be a unit circle instead of a special triangle.

Oct 15, 2015 · This is a good question indeed! I'll try to give you a visual explanation. Consider the trigonometric meaning of tangent of an angle alpha: The tangent of alpha is equal to the length of the segment AB; but when alpha becomes 90^@ the length of AB get stretched upwards (or downwards for alpha=270^@) so that we will never meet A!!! Hope it helps!

Mar 7, 2018 · How do you tell whether the value of tan 90 degrees is positive, negative, zero or undefined?

Jul 17, 2016 · We know that tan (90+a)=sin (90+a)/ (cos (90+a))= [sin90*cosa+cos90*sina]/ [cos90*cosa-sin90*sina]= [cosa]/ [-sina]=-cota Note sin90=1 , cos90=0

Sep 21, 2015 · sin (90^@)=1color (white) ("XXXXXXXXX")csc (90^@)=1 cos (90^@)=0color (white) ("XXXXXXXXX")sec (90^@) " is undefined" tan (90^@) " is undefined"color (white) ("XxXX")cot (90^@)=0 Using a unit circle (so the hypotenuse =1) and its intersection with an angular arm in standard position: the six basic trigonometric functions are defined as sin ...

Oct 20, 2015 · By definition, using a reference triangle with hypotenuse of unit length, XXXtan(θ) = length of opposite side length of adjacent side As θ → 90∘ XXXlength of opposite side → 1 and XXXlength of adjacent side → 0 1 0 is undefined ⇒ tan(90∘) is undefined.

May 8, 2018 · LHS=tan (90^@− A) sec (180^@+ A) cos (90^@+ A) =cotA (- secA) (- sin A) =cosA/sinA*1/cosA*sin A =1

Nov 12, 2013 · tan (90 ∘) is not defined. That is why you were told to use the sum of angles formulas for sine and cosine, not the sum of angles formula for tangent.

Apr 10, 2016 · The tangent of 90 degrees is not defined, and you can't divide by cot 90° which is zero.